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16 March, 14:31

30) How many grams of CH3OH must be added to water to prepare 210 mL of a solution that is

1.50 M CH3OH?

A) 10.0g

B) 48.0 g

C) 3.20 g

D) 0.210 g

E) 22.08

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Answers (1)
  1. 16 March, 14:53
    0
    Mass = 10.0 g

    Explanation:

    Given dа ta:

    Molarity = 1.50 M

    Volume = 210 mL (0.21 L)

    Grams of CH₃OH = ?

    Solution:

    Number of mole = molarity * volume

    Number of mole = 1.50 M * 0.21 L

    Number of mole = 0.315 mol

    Mass of CH₃OH:

    Mass = Number of moles * molar mass

    Mass = 0.315 mol * 32.04 g/mol

    Mass = 10.0 g
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