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18 June, 16:49

when 22 grams of water undergoes a temeprature change from 35 ˚C to 65 ˚C, how much energy does the water absorb? The specific heat of water is 4.184.

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  1. 18 June, 17:10
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    Answer: 2761.44 joules

    Explanation:

    The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

    Thus, Q = MCΦ

    Since,

    Q = ?

    Mass of oil = 22g

    C = 4.184Jg°C

    Φ = (Final temperature - Initial temperature)

    = 65°C - 35°C = 30°C

    Then, Q = MCΦ

    Q = 22g x 4.184Jg°C x 30°C

    Q = 2761.41 Joules

    Thus, water absorb 2761.44 joules of heat.
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