When solid (NH4) (NH2CO2) (NH4) (NH2CO2) is introduced into an evacuated flask at 25 ∘C∘C, the total pressure of gas at equilibrium is 0.116 atmatm. What is the value of KpKp at 25 ∘C∘C?

the value of Kp at 25°C is 2.37 * 10⁻⁴atm³

Explanation:

Given that Kp = 0.116atm

NH₄ (NH₂CO₂) (s) ⇄ 2NH₃ (g) + CO₂ (g)

2x atm xatm

Pt = PNH₃ PCO₂

0.116 = 2x + x

0.116 = 3x

x = 0.116/3

x = 0.039 atm

PNH₃ = 2x = 2 (0.039) = 0.078 atm

PCO₂ = x = 0.039 atm

Now,

KP = PNH₃² * PCO₂

= 0.078² * 0.039 atm³

= 2.37 * 10⁻⁴ atm³

the value of Kp at 25°C is 2.37 * 10⁻⁴atm³