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12 February, 11:17

A buffer solution is prepared by mixing 1.00 L of 0.050 M pentafluorobenzoic acid (C6F5COOH) and 1.00 L of 0.060 M sodium pentafluorobenzoate (NaC6F5COO). The Ka of this weak acid is 0.033. Determine the pH of the buffer solution.

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  1. 12 February, 11:40
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    pH = 1.401

    Explanation:

    Using The Henderson-Hasselbalch Equation

    pH = pKa + log [base] / [acid]

    Ka = 0.033

    pKa = - log Ka

    pKa = - log 0.033

    pKa = 1.48

    [base] = concentration of congugate base = 0.060 M

    [acid] = concentration of Acid = 0.050 M

    pH = pKa + log ([base] / [acid])

    pH = 1.48 + log (0.050 / 0.060)

    pH = 1.48 + log 0.83

    pH = 1.48 - 0.079

    pH = 1.401

    the pH of the buffer solution is 1.401
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