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9 November, 00:08

How many grams of copper (I) chloride can be produced from the reaction of 73.5 g of copper (I) oxide with hydrochloric acid according to the following reaction? Cu2O + 2 HCl à 2 CuCl + H2O

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  1. 9 November, 00:24
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    The balanced equation for the reaction is as follows

    Cu₂O + 2HCl - --> 2CuCl + H₂O

    Molar ratio of Cu₂O to CuCl is 1:2

    mass of Cu₂O reacted - 73.5 g

    Number of moles of Cu₂O reacted - 73.5 g / 143 g/mol = 0.51 mol

    According to the molar ratio,

    when 1 mol of Cu₂O reacts then 2 mol of CuCl is formed

    therefore when 0.51 mol of Cu₂O reacts then - 2 x 0.51 mol of CuCl is formed

    number of CuCl moles formed - 1.02 mol

    mass of CuCl formed - 1.02 mol x 99 g/mol = 101 g

    mass of CuCl formed is 101 g
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