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6 December, 09:54

6PbO + O2 → 2Pb304

a. How many grams of Pb304 are produced from 8.50 grams of lead (II) oxide?

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  1. 6 December, 10:20
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    8.70g of Pb3O4

    Explanation:

    6PbO + O2 → 2Pb3O4

    Molar Mass of PbO = 207 + 16 = 223g/mol

    The mass of the PbO from the balanced equation = 6 x 223 = 1338g

    Molar Mass of Pb3O4 = (3x207) + (16x4) = 621 + 64 = 685g/mol

    Mass of Pb3O4 from the balanced equation = 2 x 685 = 1370g

    From the equation,

    1338g oh PbO produced 1370g of Pb3O4.

    Therefore, 8.50g of PbO will produce = (8.5 x 1370) / 1338 = 8.70g of Pb3O4
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