What is the mass of silver that can be prepared from 2.10 g of copper metal? Cu (s) + 2AgNO3 (aq) →Cu (NO3) 2 (aq) + 2Ag (s)

Moles of Cu = 2.10 / 21 = 0.1 Moles of Ag produced is 0.2 Mass of Ag = 0.2 x 108 = 21.6 g. 0.500 g/108 = 0.046 moles, but Cu. moles produced will be half as much, from equation = 0.23moles mass of Cu = 0.023 x2.10 = 0.0483g