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16 October, 13:25

If 6 liters of hydrogen gas are used, how many liters of nitrogen gas will be needed for the above reaction at stp?

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  1. 16 October, 13:26
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    Are you referring to this reaction?

    N2 + 3H2 - - > 2NH3

    If so, then let us work it out.

    6 liters of H2 at STP is: We will be using stochiometry on the equation, therefore, in ever 3mol of H2 that you react, you have to react 1 mol of N2 too.

    6L (1000mL/L) (cm^3/mL) (m/100cm) ^3 (.0899kg/m^3) (1000g/kg) (1mol / 2.016g)

    =.2678mols of H2.

    So,

    .2678mols of H2 (1mol N2 / 3mols of H2) is. 08927 mols N2

    Then, by using the properties of nitrogen, continue working it out by doing the same conversion backwards:

    .08927mols x 28.02 g/mol x kg/1000g x 1m^3 / 1.2506kg x (100cm/m) ^3 x mL/cm^3 x L/1000mL = 2L

    Therefore, 2 Liters is required for the reaction above.
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