If we mix 25 grams of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chloride be?

The equation to solve it is NaBr + KCl - > NaCl + KBr

Theoretical yield of sodium chloride = 14.04 g

Explanation:

Given dа ta:

Mass of sodium bromide = 25 g

Theoretical yield of sodium chloride = ?

Solution:

Chemical equation:

NaBr + KCl → NaCl + KBr

Number of moles sodium bromide:

Number of moles = Mass / molar mass

Number of moles = 25.0 g / 102.9 g/mol

Number of moles = 0.24 mol

Now we will compare the moles of NaCl with NaBr.

NaBr : NaCl

1 : 1

0.24 : 0.24

Theoretical yield of sodium chloride:

Mass = moles * molar mass

Mass = 0.24 mol * 58.5 g/mol

Mass = 14.04 g