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25 June, 18:01

If I have 1.9 moles of gas held at a pressure of 4.95 atm and in a container with a volume of 5000.0 mL, what is the temperature of the gas?

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  1. 25 June, 18:16
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    158.66 K

    Explanation:

    Given that:

    Moles of the gas = 1.9 moles

    Pressure = 4.95 atm

    Volume = 5000.0 mL

    Also, 1 mL = 10⁻³ L

    So, volume = 5 L

    Using ideal gas equation as:

    PV=nRT

    where,

    P is the pressure

    V is the volume

    n is the number of moles

    T is the temperature

    R is Gas constant having value = 0.0821 L. atm/K. mol

    Applying the equation as:

    4.95 atm * 5 L=1.9 moles * 0.0821 L. atm/K. mol * T

    ⇒T = 158.66 K
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