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20 April, 06:32

2 grams of a substance was dissolved in 75.0 g of water resulting in a temperature decrease from 23.1 ⁰C to 18.7 ⁰C. The specific heat of the solution is 4.18 J/g·⁰C. Calculate the amount of heat associated with the water.

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  1. 20 April, 06:45
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    1379.4 Joules

    Explanation: The quantity of heat is calculated multiplying the mass of a substance by heat capacity and the change in temperature.

    Therefore;

    Quantity of heat = Mass * specific heat capacity * Change in temperature

    Q = mcΔT

    In this case;

    The substance dissolved in water gained heat while water lost heat energy.

    Thus, Heat gained by the substance = heat lost by water

    Heat associated with the water

    Mass of water = 75 g

    Change in temperature = 4.4°C

    Specific heat capacity = 4.18 J/g·⁰C

    Heat = mcΔT

    = 75 g * 4.18 J/g·⁰C * 4.4 °C

    =1379.4 Joules
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