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6 May, 15:59

The entropy of an exothermic reaction decreases. This reaction will be spontaneous under which of the following temperatures?

a) High temperatures

b) Low temperatures

c) All temperatures

d) No temperatures

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Answers (2)
  1. 6 May, 16:01
    0
    Answer:Low temperatures

    Explanation:

    ∆G = ∆H-T∆S

    If ∆H is negative (exothermic reaction), then in order to maintain ∆G<0 which is the condition for spontaneity; T must decrease. This is because, decrease in T will keep the difference of ∆H and T∆S at a negative value in order to satisfy the above stated condition for spontaneity.
  2. 6 May, 16:27
    0
    B - Low Temperatures

    Explanation:

    For a reaction to be spontaneous, the Gibb's free energy value has to be negative and to achieve this: the enthalpy, entropy and temperature have to meet certain criteria.

    ΔG=ΔH-TΔS

    • When the enthalpy is below 0 and entropy is above 0, the reaction

    spontaneous

    • When the enthalpy is below 0 and the entropy is above zero, the

    reaction is spontaneous only at high temperatures

    • When the enthalpy and entropy is below 0, the reaction can be

    spontaneous only at low temperatures

    • When both the enthalpy is above 0 and entropy below 0, the

    reaction cannot be spontaneous

    From the above explanation, we can infer that a decrease in entropy will require a low temperature and a low enthalpy for the reaction to be spontaneous
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