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16 February, 07:02

Question 2

20 pts

An ethylene gas torch requires 3200 L of gas at 3.00 atm. What will be the pressure of the gas if ethylene is supplied

by a 250.0 L tank?

O

0.231 atm

2.34 atm

38.4 atm

45.4 atm

+2
Answers (1)
  1. 16 February, 07:30
    0
    38.4 atm

    Explanation:

    Data obtained from the question include:

    V1 (initial volume) = 3200 L

    P1 (initial pressure) = 3.00 atm

    V2 (final volume) = 250.0 L

    P2 (final pressure) = ?

    Using Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:

    P1V1 = P2V2

    3 x 3200 = P2 x 250

    Divide both side by 250

    P2 = 3 x 3200/250

    P2 = 38.4 atm

    Therefore, the pressure of the gas if ethylene is supplied by a 250.0 L tank is 38.4 atm
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