If a sample of NH3 gas at 689,1 mmHg has a volume of 607 2 mL and the presure is

changed to 560,8 mmHg, then what will be the new volume of the NH3 gas, in militers. Be

sure to round to the correct sig digs,

Question

Amour

Chemistry

13 March, 04:02

If a sample of NH3 gas at 689,1 mmHg has a volume of 607 2 mL and the presure is

changed to 560,8 mmHg, then what will be the new volume of the NH3 gas, in militers. Be

sure to round to the correct sig digs,

+4

Answers (1)

Know the Answer?

Sharon Hamilton · Answer 1

The answer to your question is V2 = 746.1 ml

Explanation:

Data

Pressure 1 = P1 = 689.1 mmHg

Volume 1 = V1 = 607.2 ml

Pressure 2 = P2 = 560.8 mmHg

Volume 2 = V2 = ?

Process

To solve this problem use Boyle's law

P1V1 = P2V2

-Solve for V2

V2 = P1V1/P2

-Substitution

V2 = (689.1 x 607.2) / 560.8

-Simplification

V2 = 746.1 ml

If a sample of NH3 gas at 689,1 mmHg has a volume of 607 2 mL and the presure ischanged to 560,8 mmHg, then what will be the new volume of the NH3 gas, in militers. Besure to round to the correct sig digs,

If a sample of NH3 gas at 689,1 mmHg has a volume of 607 2 mL and the presure is

changed to 560,8 mmHg, then what will be the new volume of the NH3 gas, in militers. Be

sure to round to the correct sig digs,