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9 September, 09:51

Consider equimolar samples of different ideal gases at the same volume and temperature. gas a has a higher molar mass than gas b

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  1. 9 September, 10:18
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    Equal pressures from the ideal gas equation (P = nRT/V) ... same moles, T and V ... P must be the same. Lighter gas has greater RMS speed ... KE = 1/2mv² mass and speed inversely proportional

    Same KE ... all gases at same T have same KE
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