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3 December, 09:54

What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm?

Use PV = nRT and R-0.0821 Leatm

molok:

2.95 K

5.24 K

138 K

246 K

+1
Answers (2)
  1. 3 December, 10:12
    0
    246 K

    Explanation:

    6.850 mL=6.85 L

    PV=nRT

    T=PV/nR

    T = (2.21 atm * 6.85 L) / (0.750 mol * 0.0821)

    T=246 K
  2. 3 December, 10:22
    0
    It's 24k! That's the answer
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