A 5.10 g sample of iron is heated from 36.0 to 75.0 C. The amount of energy required is 89.5 J. The specific capacity of this sample of iron is ...

A.) 17800 J/g C

B.) 0.900 J/g C

C.) 11.7 J/g C

D.) 0.450 J/g C

E.) 2.22 J/g C

Question

Broderick

Chemistry

1 June, 09:57

A 5.10 g sample of iron is heated from 36.0 to 75.0 C. The amount of energy required is 89.5 J. The specific capacity of this sample of iron is ...

A.) 17800 J/g C

B.) 0.900 J/g C

C.) 11.7 J/g C

D.) 0.450 J/g C

E.) 2.22 J/g C

+5

Answers (1)

Know the Answer?

Felipe Lin · Answer 1

This can be solved from the equation q = m * C * ΔT Where q is the heat added, m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

We can rearrange the equation to find the specific heat capacity

q / (m * ΔT) = C

q = 89.5 J m = 5.10 g ΔT = (75.0 °C - 36.0 ° C) = 39 ° C

(89.5J) / (5.10 g * 39 °C) = 0.450 J/g°C

A 5.10 g sample of iron is heated from 36.0 to 75.0 C. The amount of energy required is 89.5 J. The specific capacity of this sample of iron is ...A.) 17800 J/g CB.) 0.900 J/g CC.) 11.7 J/g CD.) 0.450 J/g CE.) 2.22 J/g C

A 5.10 g sample of iron is heated from 36.0 to 75.0 C. The amount of energy required is 89.5 J. The specific capacity of this sample of iron is ...

A.) 17800 J/g C

B.) 0.900 J/g C

C.) 11.7 J/g C

D.) 0.450 J/g C

E.) 2.22 J/g C