Ask Question
11 December, 19:19

A 20.8-g sample of fuel is burned in the presence of oxygen. As a result, 9.8 grams of carbon dioxide and 17.3 grams of water are produced and captured in containers. According to the law of conservation of matter, how much oxygen reacted with the fuel?

+1
Answers (2)
  1. 11 December, 19:28
    0
    According to the law of conservation of matter, there should be 6.3 grams of oxygen reacted with the fuel

    Explanation:

    Step 1: Data given

    Mass of fuel = 20.8 grams

    In presence of oxygen, there is produced 9.8 grams of CO2 and 17.3 grams of water

    According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

    This means mass fuel + mass oxygen = mass carbon dioxide + mass water

    Mass carbon dioxide = 9.8 grams

    Mass water = 17.3 grams

    Mass CO2 + H2O = 27.1 grams

    Mass of the fuel = 20.8 grams

    This means together with the mass of the fuel, the mass of the oxygen should be 27.1 grams

    Mass oxygen = 27.1 - 20.8 = 6.3 grams

    According to the law of conservation of matter, there should be 6.3 grams of oxygen reacted with the fuel
  2. 11 December, 19:29
    0
    mass O2 = 6.3 g

    Explanation:

    X + O2 → CO2 + H2O

    ∴ X: sample of fuel

    "the mass consumed of the reagents is equal to the mass of the products obtained" ... law of conservation of matter

    ⇒ gX + gO2 = gCO2 + gH2O

    ⇒ gO2 = gCO2 + gH2O - gX

    ⇒ gO2 = 9.8 gCO2 + 17.3 gH2O - 20.8 gX

    ⇒ gO2 = 6.3 gO2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A 20.8-g sample of fuel is burned in the presence of oxygen. As a result, 9.8 grams of carbon dioxide and 17.3 grams of water are produced ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers