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1 January, 03:17

Calculate the solubility (in g/l) of calcium fluoride in water at 25°c if the ksp for caf2 is 1.5 * 10-10.

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  1. 1 January, 03:39
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    When CaF₂ dissolves, it dissociates as follows;

    CaF₂ - - > Ca²⁺ + 2F⁻

    If molar solubility of CaF₂ is x, then molar solubility of Ca²⁺ is x and F⁻ is 2x.

    ksp is solubility product constant and it can be calculated as follows;

    ksp = [Ca²⁺][F⁻]²

    ksp = (x) (2x) ²

    ksp = 4x³

    4x³ = 1.5 x 10⁻¹⁰

    x³ = 0.375 x 10⁻¹⁰

    x = 3.3 x 10⁻⁴ M

    To calculate solubility in terms of g/L, we have to know the molar mass of CaF₂.

    Solubility of CaF₂ is 3.3 x 10⁻⁴ mol/L x 78 g/mol = 0.0257 g/L
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