What is the root mean square of carbon iv oxide at 27°C?

Kinetic Energy (Translational, in all directions) of a gas as per Kinetic theory of gases at abs. Temperature T:

per molecule: KE = 3/2 * k_B T

per mole: KE = 3/2 * R * T

k_B = Boltzmann's constant. R = Universal gas constant.

Kinetic Energy of a gas (as per mechanics)

KE = 1/2 m (Vrms) ²

or KE = 1/2 M (Vrms) ²

m = mass of a molecule, M = Molar mass of the gas.

Hence, (Vrms) ² = 3 k_B T / m = 3 R T / M

R = 8.3 J/°°K/mole

M = 44 gm/mole for CO2 = 0.044 kg/mole

(Vrms) ² = 3 * 8.314 J/°K/mole * (273+27) ° / (0.044 kg/mole)

Vrms = 412.38 m/sec

Answer: not Possible

Explanation:

27 is not. square number