How many grams of nickel (+2) are required to replace all of the silver when 15.55 grams of AgNO3 are present?

Question

Anaya Parks

Chemistry

12 March, 02:28

How many grams of nickel (+2) are required to replace all of the silver when 15.55 grams of AgNO3 are present?

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Answers (1)

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Skyla Hull · Answer 1

2AgNO3 + Ni2 + = Ni (NO3) 2 + 2Ag +

From the reaction, it can be seen that AgNO3 and Ni2 + has following amount of substance relationshep:

n (AgNO3) : n (Ni) = 2:1

From the relationshep we can determinate requred moles of Ni2+:

n (AgNO3) = m/M = 15.5/169.87=0.09 moles

So, n (Ni) = n (AgNO3) / 2=0.045 moles

Finaly needed mass of Ni2 + is:

m (Ni2+) = nxM=0,045x58.7=2.64g