Calculate the enthalpy change for the thermite reaction: 2al (s) + fe2o3 (s) →2fe (s) + al2o3 (s), δh∘rxn=-850 kj when 6.00 mol of al undergoes the reaction with a stoichiometrically equivalent amount of fe2o3.

Question

Dominique Cruz

Chemistry

23 June, 08:39

Calculate the enthalpy change for the thermite reaction: 2al (s) + fe2o3 (s) →2fe (s) + al2o3 (s), δh∘rxn=-850 kj when 6.00 mol of al undergoes the reaction with a stoichiometrically equivalent amount of fe2o3.

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Adelaide Welch · Answer 1

Answer is: the enthalpy change for the thermite reaction is - 2550 kJ.

Balanced chemical reaction: Fe₂O₃ (s) + 2Al (s) → 2Fe (s) + Al₂O₃ (s).

ΔHrxn = - 850 kJ; enthalpy of thermite reaction.

n (Al) = 6.00 mol; amount of the aluminium.

From the balanced chemical reaction make proportion:

2 mol : - 850 kJ = 6 mol : ΔH.

ΔH = - 850 kJ · 6 mol : 2 mol.

ΔH = - 2550 kJ; enthalpy from 6 moles of aluminium.