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15 June, 02:18

A 40.8 mol sample of methane gas, CH4 (g), is placed in a

1020 L container at 298 K.

What is the pressure, in atm, of the methane gas?

Express the answer using 3 significant figures.

atm

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Answers (1)
  1. 15 June, 02:39
    0
    P = 0.979 atm

    Explanation:

    Given dа ta:

    Number of moles of methane = 40.8 mol

    Volume of container = 1020 L

    Temperature = 298 K

    Pressure of gas = ?

    Solution:

    According to ideal gas equation,

    PV = nRT

    P = pressure

    V = volume

    n = number of moles

    R = general gas constant

    T = temperature

    Now we will put the values,

    P = nRT/V

    P = 40.8 mol * 0.0821 atm. L/mol. K * 298 K / 1020 L

    P = 998.2 atm / 1020

    P = 0.979 atm
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