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29 April, 20:40

What volume of chlorine gas at 45.3 c is needed to react with 14.2g of sodium to form nacl at 1.72 atm?

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  1. 29 April, 21:04
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    To determine the volume of chlorine gas that is needed, we need to first know the reaction. It is expressed as follows:

    2Na + Cl2 = 2NaCl

    Then, from the amount of NaCl to be produced, we calculate the moles of Cl2 needed.

    14.2 g NaCl (1 mol / 58.44 g) (1 mol Cl2 / 2 NaCl) = 0.1215 mol Cl2

    To determine the volume of the gas, we need an equation that would relate the number of moles to volume. There are a number of equation available but some are complex equations so we assume that it is an ideal gas. We use the equation:

    PV = nRT

    V = nRT / P

    V = 0.1215 mol (0.08205 L-atm / mol-K) (45.3 + 273.15 K) / 1.72 atm

    V = 1.85 L Cl2 gas
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