What is the volume (in cm^ 3) of 1.2 moles of water vapor at RTP? Calculate the mass of this water vapor.

Volume = 29400 cm³

Mass = 21.6 g

Explanation:

Given dа ta:

Number of moles of water vapors = 1.2 mol

Mass of water vapor = ?

Volume of water vapors = ?

Solution:

Room temperature = 25 °C (25+273 = 298 K)

Room pressure = 1 atm

PV = nRT

V = nRT/P

V = 1.2 mol * 0.0821 atm. K⁻¹. mol⁻¹. L * 298 K / 1 atm

V = 29.4 L

In cm³:

29.4 * 1000 = 29400 mL

mL = cm³

Mass of water vapors:

Mass = number of moles * molar mass

Mass = 1.2 mol * 18 g/mol

Mass = 21.6 g