What mass of ammonia is formed when 3.75 grams of nitrogen gas react with hydrogen gas according to the balanced chemical equation: N2 (g) + 3H2 (g) - -> 2NH3 (g) ?

3.75 g

4.55 g

7.50 g

9.10 g

Mass = 4.55 g

Explanation:

Given data;

Mass of nitrogen = 3.75 g

Mass of ammonia produced = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Number of moles of nitrogen:

Number of moles = mass / molar mass

Number of moles = 3.75 g / 28 g/mol

Number of moles = 0.134 mol

Now we compare the moles ammonia with nitrogen

N₂ : NH₃

1 : 2

0.134 : 2/1 * 0.134 = 0.268 mol

Theoretical yield:

Mass = number of moles * molar mass

Mass = 0.268 mol * 17 g/mol

Mass = 4.55 g