I'm trying to learn molarity problems on my own (online schooling is terrible), I don't need the answer for the following problem as much as I need the process of solving it explained

How many L of solution are present if 100g NaCl has been dissolved in water to make a 2.50M solution?

0.68L

Explanation:

First, let us calculate the number of mole in 100g of NaCl. This is illustrated below:

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl = 100g

Number of mole of NaCl = ?

Number of mole = Mass/Molar Mass

Number of mole of NaCl = 100/58.5

Number of mole of NaCl = 1.709 mole

Now we can find the volume of the solution as follow:

Mole = 1.709 mole

Molarity = 2.50M

Volume = ?

Molarity = mole / Volume

Volume = mole / Molarity

Volume = 1.709/2.5

Volume = 0.68L