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25 December, 12:01

Reactant A contains 85.1 J of chemical energy. Reactant B contains 87.9 J of chemical energy. Product C contains 38.7 J of chemical energy. If the reaction absorbs 104.3 J of chemical energy as it proceeds, how much chemical energy must product D contain?

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Answers (2)
  1. 25 December, 12:10
    0
    The reaction would proceed like: A + B - - > C + D. We then consider that each has a stoichiometric coefficient of 1 for each of the reactant and product. Hence, algebraically, this problem can be presented as follows:

    (38.7+X) - (85.1+87.9) = - 104.3

    Then x = 31 J

    This is the amount of energy D must contain.
  2. 25 December, 12:18
    0
    Answer: 238.6 J

    Explanation:

    1) Chemical energy is indicated as enthalpy

    2) Energy balance:

    ∑ enthalpy of the reactants + energy added = ∑ enthalpy of the products + energy released.

    3) ∑ enthalpy of the reactants = 85.1 J + 87.9 J = 173 J

    4) energy added = 104.3 J

    5) ∑ enthalpy of the products = 38.7 J + D

    6) energy released = 0

    7) Equation:

    173J + 104.3J = 38.7 + D + 0

    ⇒ D = 173J + 104.3J - 38.7J = 238.6J, which is the chemical energy of the product D.
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