A 8.6 g rock sample is added to a graduated cylinder filled with water, causing the level to increase from 12.8 mL to 13.6 mL. What is the density of the rock sample?

From the given variable values, we can calculate the density of the rock sample to be = 10750_Kg/m^3

Explanation:

To solve this question, we recollect that density is the mass per unit volume of a substance and the SI unit of density is Kg/m^3 with symbol

ρ

The given variables are as follows

mass of rock sample = 8.6g

The volume displaced in the graduated cylinder is

(Final volume level of the cylinder) - (initial volume level of the cylinder)

13.6ml - 12.8 ml = 0.8ml = volume of the rock sample

Therefore, density = 8.6/0.8 = 10.75g/ml = or 1000*10.75 Kg/m^3 = 10750Kg/m^3

Density of the rock sample is 10750Kg/m^3