You have a mixture of the noble gases Xe, Ne, and He at 6.0 atm. The partial pressure of Xe is 2.7 atm and the mole fraction of Ne is 0.2500. What is the partial pressure of He in this mixture?

Question

Bonnie

Chemistry

17 November, 19:15

You have a mixture of the noble gases Xe, Ne, and He at 6.0 atm. The partial pressure of Xe is 2.7 atm and the mole fraction of Ne is 0.2500. What is the partial pressure of He in this mixture?

+5

Answers (1)

Know the Answer?

Draven Padilla · Answer 1

The partial pressure of He = 1.8 atm

Explanation:

Step 1: Data given

The total mass = 6.0 atm

Partial pressure of Xe = 2.7 atm

Mol fraction of Ne = 0.2500

Step 2: Calculate partial pressure of Ne

Partial pressure Ne = total pressure * mol fraction

Partial pressure Ne = 6.0 atm * 0.2500

Partial pressure Ne = 1.5 atm

Step 3: Calculate the partial pressure of He

Total pressure = partial pressure of Xe + partial pressure of Ne + partial pressure of He

6.0 atm = 2.7 atm + 1.5 atm + pHe

pHe = 6.0 - 2.7 - 1.5

pHe = 1.8 atm

The partial pressure of He = 1.8 atm