Zn (OH) 2 SnO22-Zn SnO32 - H2O In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent. name of the element oxidized: name of the element reduced: formula of the oxidizing agent: formula of the reducing agent:

Question

Donovan Banks

Chemistry

31 May, 13:23

Zn (OH) 2 SnO22-Zn SnO32 - H2O In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent. name of the element oxidized: name of the element reduced: formula of the oxidizing agent: formula of the reducing agent:

+3

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Yazmin Bowen · Answer 1

Zn (OH) ₂ + SnO₂⇄ ZnSnO₃ + H₂O

In this reaction, nothing is oxidised, nor is anything reduced.

oxidation number of Zn in Zn (OH) ₂ is + 2,

oxidation number of Zn in ZnSnO₃ is also + 2.

oxidation number of Sn in SnO₂ is + 4,

oxidation number of Sn in ZnSnO₃ is also + 4.

Oxidation no of oxygen and hydrogen also remains unchanged at - 2 and + 1

respectively.

So it is not a redox reaction.