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23 February, 03:40

How many grams of calcium chloride will be produced when 28.0 g 28.0 g of calcium carbonate is combined with 14.0 g 14.0 g of hydrochloric acid?

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Answers (2)
  1. 23 February, 03:42
    0
    There will be 21.31 grams of CaCl2 produced.

    Explanation:

    Step 1: Data given

    Mass of CaCO3 = 28.0 grams

    Mass of HCl = 14.0 grams

    Molar mass of CaCO3 = 100.09 g/mol

    Molar mass of HCl = 36.46 g/mol

    Step 2: The balanced equation

    CaCO3 + 2HCl → CaCl2 + H2O + CO2

    Step 3: Calculate Moles of CaCO3

    Moles CaCO3 = mass CaCO3 / molar mass CaCO3

    Moles CaCO3 = 28.0 grams / 100.09 g/mol

    Moles CaCO3 = 2.80 moles

    Step 4: Calculate moles HCl

    Moles HCl = 14.0 grams / 36.46 g/mol

    Moles HCl = 0.384 moles

    Step 5: Calculate the limiting reactant.

    For 1 mol CaCO3 we need 2 moles HCl to produce 1 mol caCl2, 1 mol CO2 and 1 mol H2O

    HCl is the limiting reactant. It will completely be consumed (0.384 moles)

    CaCO3 is in excess. There will react 0.384/2 = 0.192 moles

    There will remain 2.80 - 0.192 = 2.608 moles

    Step 6: Calculate moles CaCl2

    For 1 mol CaCO3 we need 2 moles HCl to produce 1 mol caCl2, 1 mol CO2 and 1 mol H2O

    For 0.384 moles HCl we'll have 0.384/2 = 0.192 moles CaCl2

    Step 7: Calculate mass CaCl2

    Mass CaCl2 = moles CaCl2 * molar mass

    Mass CaCl2 = 0.192 moles * 110.98 g/mol

    Mass CaCl2 = 21.31 grams

    There will be 21.31 grams of CaCl2 produced.
  2. 23 February, 03:52
    0
    21.3 g of CaCl₂ are produced in this reaction

    Explanation:

    Reaction is this:

    CaCO₃ + 2HCl → CaCl₂ + H₂CO₃

    Molar mass salt : 100.08 g/m

    Molar mass acid: 36.45 g/m

    We have 28 g / 100.08 g/m = 0.279 moles of CaCO₃

    We have 14 g / 36.45 g/m = 0.384 moles of HCl

    Ratio is 1:2, so 0.279 moles of salt will need the double of moles of acid.

    0.279. 2 = 0.558 moles of acid needed. (I have only 0.384 moles, so the acid is the limiting reactant)

    0.384 moles of HCl produce the half of moles of CaCl₂ (This ratio is 1:2) - -> 0.192 moles

    Molar mass of CaCl₂ = 110.98 g/m

    Mol. molar mass = mass → 0.192 m. 110.98 g/m = 21.3 g
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