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20 March, 21:26

What is the poH of a solution that

contains [OH]=4.65 x 10^-7 M?

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Answers (1)
  1. 20 March, 21:31
    0
    pOH = 6.33

    Explanation:

    pOH = - log{OH-} = - log[4.65*10^-7] = 6.33
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