Ask Question
19 January, 07:29

A sample of 3.785 g of a compound is analyzed, and found to contain 1.302 g Fe and 2.483 g Cl. Another sample of the compound is found to contain 2.329 g of Cl. How many grams of Fe will it contain

+4
Answers (2)
  1. 19 January, 07:32
    0
    Defining law of simple multiple proportions, which states that when two or more elements form more than one compound, the ratio of the weights of one element that combine with a given weight of another element in the different compounds is a ratio of small whole numbers

    Ratio of Fe and Cl in the first sample is:

    Mass of Fe: Mass of Cl

    1.302 : 2.483

    Ratio = 1 : 1.9

    Therefore, in the other sample;

    Mass of Fe: Mass of Cl

    = 1 : 1.9

    = x : 2.329

    x = 2.329 : 1.9

    = 1.221 g.
  2. 19 January, 07:38
    0
    1.221g

    Explanation:

    First Sample

    Ratio of Fe and Cl is given as;

    Mass of Fe: Mass of Cl

    1.302g : 2.483g

    Second Sample;

    Mass of Fe: Mass of Cl

    xg : 2.329g

    The ratio between both elements is constant in both samples, so we have;

    Ratio of first sample = Ratio of second sample

    1.302g : 2.483g = xg : 2.329g

    1.302 / 2.483 = x / 2.329

    x = (2.329 * 1.302) / 2.483

    x = 1.221g
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A sample of 3.785 g of a compound is analyzed, and found to contain 1.302 g Fe and 2.483 g Cl. Another sample of the compound is found to ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers