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14 September, 06:43

He concentration of pb2 + in a commercially available standard solution is 1.00 mg/ml. what volume of this solution should be diluted to 5.0*102 ml to produce a solution in which the concentration of pb2 + is 0.055 mg/l?

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  1. 14 September, 07:06
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    This can be directly solved using the formula:

    C1 V1 = C2 V2

    where C is concentration and V is volume

    1.00 mg/ml * V1 = 0.055 mg/1000 ml * (5.0 x 10^2 ml)

    V1 = 0.0275 ml

    So 0.0275 ml is needed to be diluted to 5.0 x 10^2 ml
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