What is the theoretical yield of moles of hydrogen that can be produced from 0.032g of MG?

1.31x10⁻³ moles of H₂

Explanation:

This is the equation:

Mg (s) + 2H₂O (g) → Mg (OH) ₂ (aq) + H₂ (g)

Ratio is 1:1, so 1 mol of Mg is needed to produce 1 mol of H₂

Mass / Molar mass = Mol

0.032 g / 24.3 g/m = 1.31x10⁻³ moles

1.31x10⁻³ moles of H₂ (g)