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We dissolve 5g of sugar, C12H22O11, in water to make 1L solution. What is the concentration of this solution expressed as molarity.

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  1. Today, 00:03
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    Answer: M = 0.01 M C12H22O16

    Explanation: First convert the mass of C12H22O16 into moles using the molar mass of the compound.

    5 g C12H22O16 x 1 mole C12H22O16 / 342 g C12H22O16

    = 0.01 mole C12H22O16

    To calculate the molarity we will use the following formula.

    M = n / L

    = 0.01 mole / 1 L

    = 0.01 M C12H22O16
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