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21 January, 14:06

Use Hess's Law or the summation equation to calculate the ΔHrxn. Round to the nearest tenth!

___NF (g) + ___F2 (g) - -> ___NF2 (g)

½N2 (g) + ½F2 (g) - > NF (g) Hf = 86.6 kJ

½N2 (g) + F2 (g) - > NF2 (g) Hf = 33.8 kJ

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  1. 21 January, 14:23
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    The ΔHrxn with the nearest tenth will have value of - 60 K.

    Explanation:

    NF (g) + ___F2 (g) - -> ___NF2 (g

    data given:

    ½N2 (g) + ½F2 (g) - > NF (g) Hf = 86.6 kJ

    ½N2 (g) + F2 (g) - > NF2 (g) Hf = 33.8 kJ

    Hess's law of heat is summation says that total change in enthalpy during a reaction is same whether the reaction is direct or in various steps.

    ½N2 (g) + ½F2 (g) - > NF (g) Hf = 86.6 kJ

    reversing the equation we get:

    NF - > ½N2 (g) + ½F2 (g)

    Heat of enthalpy becomes negative so - 86.6 KJ

    Now adding both the reactions:

    NF - > ½N2 (g) + ½F2 (g)

    ½N2 (g) + F2 (g) - > NF2 (g) Hf = 33.8 kJ

    Removing the common entities from the reaction we get

    F2 (g) + NF (g) - -> ½F2 (g) + NF2 (g) Hf

    the summation of enthalpy is

    -86.6 + 33.8

    = 52.8 KJ

    The nearest tenth will be - 60 KJ.
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