Ask Question
10 April, 19:11

7. How many moles of argon are there in 20.0 L, at 25 degrees Celsius and 96.8 kPa?

+2
Answers (2)
  1. 10 April, 19:17
    0
    0.8133 mol

    Solution:

    Data Given:

    Moles = n = ?

    Temperature = T = 25 °C + 273.15 = 298.15 K

    Pressure = P = 96.8 kPa = 0.955 atm

    Volume = V = 20.0 L

    Formula Used:

    Let's assume that the Argon gas is acting as an Ideal gas, then according to Ideal Gas Equation,

    P V = n R T

    where; R = Universal Gas Constant = 0.082057 atm. L. mol⁻¹. K⁻¹

    Solving Equation for n,

    n = P V / R T

    Putting Values,

    n = (0.955 atm * 20.0 L) : (0.082057 atm. L. mol⁻¹. K⁻¹ * 298.15 K)

    n = 0.8133 mol
  2. 10 April, 19:26
    0
    The moles of argon that are there in 20.0 L, at 25 c and 96.8 KPa is = 0.7814 moles

    calculation

    by use of the ideal gas equation

    that is PV=nRT where;

    P (pressure) = 96.8 kpa

    V (volume) = 20.0 L

    n (moles) = ?

    R (gas constant) = 8.314 kpa/k/mol

    T (temperature) = 25 + 273 = 298 K

    make n the formula of the subject

    n = PV/RT

    n is therefore = [ (96.8 KPa x 20.0 l) / (8.314 kpa/k/mol x 298 k) ]

    answer = 0.781 moles
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “7. How many moles of argon are there in 20.0 L, at 25 degrees Celsius and 96.8 kPa? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers