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30 August, 07:00

What volume (mL) of 1.50 * 10-2 M hydrochloric acid can be neutralized with 115 mL of 0.244 M sodium hydroxide?

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  1. 30 August, 07:02
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    Answer: 1870. 67mL

    Explanation:

    NaOH + HCl - > NaCl + H2O

    nA = 1, Ca = 0.015M, Va = ?

    nB = 1 Cb = 0.244 M, Vb = 115 mL

    CaVa / CbVb = nA/nB

    (0.015xVa) / (0.244x115) = 1/1

    Va = (0.244x115) / 0.015 = 1870. 67mL
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