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5 September, 14:55

If you have 6 moles of reactant A and excess of B and C, how much product E would be formed? 3A+5B+1C=>2D+1E

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  1. 5 September, 15:06
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    From the reaction you can state the molar ratios:

    3 mol A : 5 mol B : 1 mol C : 2 mol D : 1 mol E.

    Given that B and C are in excess, you know that reactant A is the limiting reactant, which means that is reacts completely. So, you can use the number of moles of reactant B to find how many moles of the products are produced.

    For that, you build a proportion with the molar ratios between A and E, and the number of moles of A that reacted:

    => 3 mol A / 1 mol E = 6 mol A / x = > x = 6 mol A * 1 mol E / 3 mol A

    => x = 6*1/3 mol E = 2 mol E.

    Answer: 2 moles of E.
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