If the reaction of 3.50 moles of lithium with excess hydrofluoric acid produced a 75.5% yield of hydrogen gas, what was the actual yield of hydrogen gas? unbalanced equation: li + hf lif + h2 1.32 mol h2 1.75 mol h2 2.32 mol h2 2.65 mol h2

Question

Larissa Hansen

Chemistry

26 July, 21:57

If the reaction of 3.50 moles of lithium with excess hydrofluoric acid produced a 75.5% yield of hydrogen gas, what was the actual yield of hydrogen gas? unbalanced equation: li + hf lif + h2 1.32 mol h2 1.75 mol h2 2.32 mol h2 2.65 mol h2

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Answers (1)

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Kiana Vance · Answer 1

Balanced chemical equation is as follows

2Li + 2HF - - - >2 Li + H2

from reaction above 2 moles of Li react with 2 moles of HF to form 2 moles of Li and 1 mole of H2

we know the mole of Li is 3.50 moles

Since ratio of Li to H2 is 2:1 then the mole of H2 is 1/2 x3.50=1.75moles