How many moles of PbCl4 are needed to produce 2.00 g of Cl ions?

Question

Vaughn Wallace

Chemistry

22 March, 22:33

How many moles of PbCl4 are needed to produce 2.00 g of Cl ions?

+3

Answers (1)

Know the Answer?

Gemma · Answer 1

Answer is: 0,014 moles of PbCl₄ are needed.

Chemical dissociation: PbCl₄ → Pb⁴⁺ + 4Cl⁻.

m (Cl⁻) = 2,00 g.

n (Cl⁻) = m (Cl⁻) : M (Cl⁻).

n (Cl⁻) = 2 g : 35,45 g/mol.

n (Cl⁻) = 0,056 mol.

From chemical reaction: n (Cl⁻) : n (PbCl₄) = 4 : 1.

n (PbCl₄) = 0,056 mol : 4.

n (PbCl₄) = 0,014 mol = 1,4·10⁻² mol.