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29 October, 10:48

How long would it take for 1.50 mol of water at 100.0 âc to be converted completely into steam if heat were added at a constant rate of 20.0 j/s? express your answer to three significant figures and include the appropriate units?

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  1. 29 October, 10:55
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    To convert boiling water to steam, that would involve heat of vaporization. The heat of vaporization for water at atmospheric conditions is: ΔHvap = 2260 J/g.

    Molar mass of water = 18 g/mol

    Q = m ΔHvap = (1.50 mol water) (18 g/mol) (2260 J/g) = 61,020 J

    Time = Q/Rate = (61,020 J) (1 s/20 J) = 3051 seconds

    In order to express the answer in three significant units, let's convert that to minutes.

    Time = 3051 s * 1min/30 s = 102 min
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