What amount of moles does 60.5 L of carbon dioxide occupy at 2.15 atm and 25 degrees C?

4.3 moles

5.3 moles

9.3 moles

2.5 moles

Answer: 5.3 moles

Explanation:

Hi, to answer this question we have to apply the next formula:

n = PV/RT

Where:

n = number of moles

P = Pressure = 2.15 atm

V = volume = 60.5 L

R = 0.0821 atm (L) / mol (K)

T = temperature = 25 ° + 273.15 = 298.15 Kelvin

Replacing with the values given:

n = 2.15 (60.5) / 0.0821 (298.15) = 5.3 moles.

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