Consider the reaction: hcl (aq) + naoh (aq) → naoh (aq) + h2o (l) how much 0.113 m naoh solution will completely neutralize 1.25 l of 0.228 m hcl solution? express your answer in liters to three significant figures.

The amount of NaOH formed is 2.522 L

calculation

HCl + NaOH → NaCl + H2O

Step 1:find the moles of HCl = molarity x volume in liters

= 1.25 l x 0.228 M = 0.285 moles

step 2: use the mole ratio to calculate the moles of NaOH

the mole ratio of NaOH:HCl = 1:1 therefore the moles of NaOH is also

= 0.285 moles

Step 3: find the volume of NaOH

volume = moles / molarity

= 0.285 / 0.113 = 2.522 L