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26 October, 08:10

100 ml of gaseous hydrocarbon consumes 300

ml of oxygen for the complete combustion.

The hydrocarbon is

a. C2H4

b. C2H2

C. C3H8

d. C2H6

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Answers (2)
  1. 26 October, 08:33
    0
    The answer would be a. C2H4 (ethylene)

    1C2H4+3O2~>2CO2+2H2O
  2. 26 October, 08:35
    0
    a. C2H4.

    Explanation:

    Let's look at the balanced equation for C2H4.

    C2H4 + 3O2 - -> 2CO2 + 2H2O

    So 1 mole of this hydrocarbon reacts with 3 moles of oxygen and since 1 mole of one gas occupies the same volume as another gas, the volumes will be in the ratio 1:3. So this is the required hydrocarbon.
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