In the United States, volume of irrigation water is usually expressed in acre-feet. One acre-foot is a volume of water sufficient to cover 1 acre of land to a depth of 1 ft (640 acres = 1 mi2, 1 mi = 5280 ft). The principal lake in the California Water Project is Lake Oroville, whose water storage capacity is listed as 3.54 x 106 acre-feet. Express the volume of Lake Oroville in (a) cubic feet, (b) cubic meters, and (c) US gallons.

Question

Massey

Chemistry

18 October, 01:08

In the United States, volume of irrigation water is usually expressed in acre-feet. One acre-foot is a volume of water sufficient to cover 1 acre of land to a depth of 1 ft (640 acres = 1 mi2, 1 mi = 5280 ft). The principal lake in the California Water Project is Lake Oroville, whose water storage capacity is listed as 3.54 x 106 acre-feet. Express the volume of Lake Oroville in (a) cubic feet, (b) cubic meters, and (c) US gallons.

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Answers (1)

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Kyson Ramirez · Answer 1

a) V = 1.542 E11 ft³

b) V = 4367011968 m³

c) V = 1.1535 E12 us gal

Explanation:

Acre surface is defined as 66 by 660 feet at a depth of one foot:

⇒ Vacre-foot = 66ft*660ft*1ft = 43560 ft³

lake:

a) V = 3.54 E6 acre-feet * (43560 ft³ / acre-foot) = 1.542 E11 ft³

b) V = 1.542 E11 ft³ * (0.02832m³ / ft³) = 4367011968 m³

c) V = 1.542 E11 ft³ * (7.48052 us gal/ft³) = 1.1535 E12 us gal