How many grams of zinc metal will react completely with 8.2 liters of 3.5 M HCl? Show all of the work needed to solve this problem.

Zn (s) + 2 HCl (aq) ZnCl2 (aq) + H2 (g)

The balanced chemical reaction is:

Zn (s) + 2 HCl (aq) - - - > ZnCl2 (aq) + H2 (g)

We are given the amount of the hydrochloric acid to be used in the reaction. This will be used for the calculations.

3.5 mol/L HCl (8.2 L) (1 mol Zn / 2 mol HCl) (65.38 g / 1 mol) = 938.20 g Zn