Ask Question
20 April, 21:54

How many moles of Fe2O3 are in 209 g of the compound?

+3
Answers (1)
  1. 20 April, 22:01
    0
    M = 209g

    M = 56 * 2 + 16 * 3 = 160 g/mol

    n = m/M = 209g / 160 g/mol = 1,30625mol
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “How many moles of Fe2O3 are in 209 g of the compound? ...” in 📗 Chemistry if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers